Problem statement;
You need to find combination of stock brought and sell with maximum profile if brought and sold only once
Ex.if I purchase stock 4th day and sold at 7th day max profile will be 6 any other combination would have lesser profit.
Out out is 4th day 7th day amount is 6.
import java.util.Scanner;
/**
* @author Gaurang Sheth
* Largest Sum Contiguous Subarray
*/
public class TestMain {
* @author Gaurang Sheth
* Largest Sum Contiguous Subarray
*/
public class TestMain {
//Test input - -2 1 -3 4 -1 2 1 -5 4
public static void main(String[] args) {
//System.out.println( compStr(null));
System.out.println("Enter size of array :");
public static void main(String[] args) {
//System.out.println(
System.out.println("Enter size of array :");
//Scanner scan = new Scanner(System.in);
int n = Integer.parseInt(args[0]);
int[] arr = new int[n];
for (int i = 0; i < n; i++) {
arr[i] = Integer.parseInt(args[i+1]);
}
System.out.println(n);
System.out.println(arr. toString());
int maxSum = 0;
String s="";
for (int j = 0; j < n; j++) {
//int x = n;
for (int x = n; x > j ; x--) {
int sum = 0;
for (int i = j; i < x ; i++) {
sum += arr[i];
}
System.out.println("Start" +j+ " End "+ x+"--SUM -- >"+sum);
if(sum > maxSum){
maxSum = sum;
s = "Start"+j+ " End "+ x;
}
}
}
System.out.println(s +" - "+maxSum);
}
//-2 1 -3 4 -1 2 1 -5 4
int n = Integer.parseInt(args[0]);
int[] arr = new int[n];
for (int i = 0; i < n; i++) {
arr[i] = Integer.parseInt(args[i+1]);
}
System.out.println(n);
System.out.println(arr.
int maxSum = 0;
String s="";
for (int j = 0; j < n; j++) {
//int x = n;
for (int x = n; x > j ; x--) {
int sum = 0;
for (int i = j; i < x ; i++) {
sum += arr[i];
}
System.out.println("Start"
if(sum > maxSum){
maxSum = sum;
s = "Start"+j+ " End "+ x;
}
}
}
System.out.println(s +" - "+maxSum);
}
//-2 1 -3 4 -1 2 1 -5 4
}